- #1

- 295

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The answer to this is up (d).

But why?

Is it because centripetal acceleration is pointing to the center of the pivot?

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- Thread starter riseofphoenix
- Start date

- #1

- 295

- 2

The answer to this is up (d).

But why?

Is it because centripetal acceleration is pointing to the center of the pivot?

- #2

- 295

- 2

This is what I did:

F = gm

F

F

F

I don't know where to go from here :(

- #3

- 33

- 0

I believe this is correct.Is it because centripetal acceleration is pointing to the center of the pivot?

In regards to how you should go about finding the gravitational acceleration you would feel on Jupiter, keep in mind that you are supposed to be finding acceleration. You look like you were solving for the force Jupiter will exert on an object, not the acceleration of gravity on Jupiter. This is a problem because the force that Jupiter will exert on an object depends on the mass of the object. It is true that

F

What else is F

- #4

- 295

- 2

I believe this is correct.

In regards to how you should go about finding the gravitational acceleration you would feel on Jupiter, keep in mind that you are supposed to be finding acceleration. You look like you were solving for the force Jupiter will exert on an object, not the acceleration of gravity on Jupiter. This is a problem because the force that Jupiter will exert on an object depends on the mass of the object. It is true that

F_{g}= G Mm/r^{2}

What else is F_{g}equal to? Could you use that relationship to find the acceleration on Jupiter?

Fg = ma

So I would do this?

mg = g

(1.9 x 10

(1.9 x 10

1.86 x 10

1.86 x 10

50239.89 = g

5.02 x 10

That's wrong :(

- #5

Chestermiller

Mentor

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- #6

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_{Jupiter}in the right hand side of the equation? G is a universal constant, and not related specifically to Jupiter. And where did the 9.81 come from? We are talking about Jupiter, not earth. In you most recent post, m is equal to m_{2}, and g is what you are solving for; m_{2}is the mass of Jupiter.

So,

mg = (6.67 x 10

(1.9 x 10

What about m

- #7

Chestermiller

Mentor

- 21,475

- 4,854

So,

mg = (6.67 x 10^{-11})m_{1}(1.9 x 10^{27})/71.492^{2}

(1.9 x 10^{27})g = (6.67 x 10^{-11})m(1.9 x 10_{1}^{27})/71.492^{2}

What about m_{1}??

I'm sorry. I made a typo in my previous reply. Please excuse me. It should have read:

m = m

m

- #8

- 33

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m = m2 = your mass

Just to explain this a little more to hopefully help riseofphoenix understand it: you can't plug in the mass of Jupiter to find the force Jupiter exerts on the object. Doing so would be like trying to find my weight (also known as the force that the Earth exerts on me) with the equation

w = m

That doesn't really make sense, does it? Hopefully not! If I want to find my weight, I need to use my mass! Thus to find the force that Jupiter exerts on the object, you have to multiply the mass of the object by the gravitational acceleration on Jupiter, which is why the mass of the object appears on the left side of your equation. Then you can see that the mass of the object cancels out since it is on both sides of the equation and you are left with an equation containing only known variables.

- #9

- 295

- 2

I'm sorry. I made a typo in my previous reply. Please excuse me. It should have read:

m = m_{2}= your mass

m_{1}= mass of Jupiter

This is what i did:

[STRIKE]m

g = (6.67 x 10

g = (1.2673 x 10

g = 2.479 x 10

???

Last edited:

- #10

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- #11

- 295

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g = (6.67 x 10

g = (1.2673 x 10

Thanks!

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